SOLUTION: find two numbers which differs by 5 and sum of their squares are 125.

Question 470851: find two numbers which differs by 5 and sum of their squares are 125.
Answer by hinaahsan(5) (Show Source): You can put this solution on YOUR website!
let the two numbers be x and x-5
(x)^2 + (x-5)^2 = 125
x^2 + x^2 + 25 -10x =125
2x^2 - 10x +25 =125
2x^2 -10x= 125-25
2x^2 -10x =100
2x(x-10) = 100
x(x-10) = 100/2
x(x-10)=50
x^2-10x-50 = 0
x^2 -10x +5x -50 =0
x(x-10) +5(x-10) =0
(x+5)(x-10) = 0
(x+5) = 0 ; (x-10)=0
x= -5 ; x=10
so the two numbers be -5 and 10
Counter check
(-5)^2 + (10)^2
= 25+100
= 125
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