SOLUTION: In triangle ACB a=230 ft b=110 ft angle C=34 degrees can you help me find side c? I got 152 is that what you got?

Question 458308: In triangle ACB
a=230 ft
b=110 ft
angle C=34 degrees
can you help me find side c?
I got 152 is that what you got?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In triangle ACB
a=230 ft
b=110 ft
angle C=34 degrees
can you help me find side c?
-----------------
Use Law of Cosines:
c^2 = a^2+b^2-2abCos(C)
---
c^2 = 230^2+110^2-2*230*110*cos(34)
---
c^2 = 23050.70
c = 151.82
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Cheers,
Stan H.
==============
I got 152 is that what you got?
That's what I got.
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