SOLUTION: The sum of the squares of two consecutive positive odd integers is 202. Find the numbers.
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Question 456397: The sum of the squares of two consecutive positive odd integers is 202. Find the numbers.
Found 2 solutions by tinbar, Alan3354:
Answer by tinbar(133) (Show Source): You can put this solution on YOUR website!
if we have some number x, then it's consecutive will be x+1
so in math language, the question asks you to solve (x)^2 + (x+1)^2 = 202
2x^2+2x+1=202
2x^2+2x-201 = 0
use the quadratic formula and solve for x!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The sum of the squares of two consecutive positive odd integers is 202. Find the numbers.
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202/2 = 101
sqrt(101) = about 10, the center
--> 9 & 11
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