SOLUTION: the perimiter of a rectangle is 42cm the length is 3 cm greater than the width find the width and length
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Question 452167: the perimiter of a rectangle is 42cm the length is 3 cm greater than the width find the width and length
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
We can set up the following equation as:
(W is width and W+3 is length)
2W+2(W+3)=42
Combine like terms:
4W+6=42
Subtract 65 and divide by 4 to get:
W=9 cm Now we know the length is:
L=12 cm
Make sense?
RJ
www.math-unlock.com
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