# SOLUTION: The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inc

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 Click here to see ALL problems on Miscellaneous Word Problems Question 451215: The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Fine the dimensions of the original rectangleAnswer by lwsshak3(6469)   (Show Source): You can put this solution on YOUR website!The length of a rectangle is twice the width. If the length is increased by 4 inches and the width is diminished by 1 inch, a new rectangle is formed whose perimeter is 198 inches. Fine the dimensions of the original rectangle .. let x=original length=2y let y=original width length increased by 4=x+4 width deminished by 1=y-1 Perimeter=2*length+2*width=198 2(x+4)+2(y-1)=198 2x+8+2y-2=198 substitute x for 2y 2x+8+x-2=198 3x=192 x=64 inches y=x/2=64/2=32 inches Ans: Dimensions of original triangle: 64 by 32 inches