Hi,

Find the z-scores for which 98% of the distribution's area lies between -z and z.  

That is: .01 < P < .99  NORMSINV(0.01) = -2.33  AND NORMSINV(0.99) = 2.33

 See below: distribution area is between the short vertical green lines.

short vertical lines plotted at z = -2.33 and z = 2.33

 

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