SOLUTION: Mixture problem: A mechanic needs a radiator to have a 40% antifreeze solution. the radiator currently is filled with 4 gallons of a 25% antifreeze solution. How much of the ant

Question 449381: Mixture problem: A mechanic needs a radiator to have a 40% antifreeze solution. the radiator currently is filled with 4 gallons of a 25% antifreeze solution. How much of the antifreeze mixture should be drained from the car if the mechanic replaces it with pure antifreeze?
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
4x.4=1.6
.25(4-x)+x=1.6
1-.25x+x=1.6
.75x=.6
x=.6/.75=.8
The mechanic need to remove .8 gallons of the anti-freeze he/she's got in the radiator, and replace it with .8 gallons of pure antifreeze to get the desired solution.
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