SOLUTION: Fred's retangular dog pen must have an area of 400 square feet. Also the length must be 12 feet longer then the width. Find the dimensions of the pen. The width of the pen is

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Question 436858: Fred's retangular dog pen must have an area of 400 square feet. Also the length must be 12 feet longer then the width. Find the dimensions of the pen.
The width of the pen is
The length of the pen is
(Simplify your answer. Type a exact answer, using radicls as needed)

Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
Area=LxW
(x+12)x=400
x2+12x-400=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1744 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 14.8806130178211, -26.8806130178211. Here's your graph:

Throwing out the negative answer, we get width=14.88, and length to be 26.88.

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