SOLUTION: Given a>b and (a-b)>(a^2-b^2), then (a+b)must be:
a)less than 1., b)greater than 1.,c)greater than a., d)greater than (a-b)., e)equal to (a-b).
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-> SOLUTION: Given a>b and (a-b)>(a^2-b^2), then (a+b)must be:
a)less than 1., b)greater than 1.,c)greater than a., d)greater than (a-b)., e)equal to (a-b).
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Question 434002: Given a>b and (a-b)>(a^2-b^2), then (a+b)must be:
a)less than 1., b)greater than 1.,c)greater than a., d)greater than (a-b)., e)equal to (a-b). Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! a > b ==> a - b > 0.
Now , or . Since a - b is known to be positive we can divide both sides of the last inequality by a - b, without changing the direction of the inequality sign, so that
1 > a + b.
Hence the answer is letter a.
