SOLUTION: A coin box has $3.25 consisting of nickels and dimes. The number of dimes is 5 less than twice the number of nickels. How many of each kind are in the box?
Algebra.Com
Question 430858: A coin box has $3.25 consisting of nickels and dimes. The number of dimes is 5 less than twice the number of nickels. How many of each kind are in the box?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
nickels ---------x
dimes-----------(2x-5)
Value= 325
5x+20x -50=325
25x-50=325
25x=325+50
25x=375
/25
x=15 nickels
Dimes = 2x-5= 25
RELATED QUESTIONS
a cashier has 25 coins consisting of nickels dimes and quarters with a value of $4.90.... (answered by lwsshak3)
A cashier has 25 coins consisting of nickels, dimes, and quarters with a value of $4.90.... (answered by stanbon)
Jesse has 38 nickels and dimes. The number of nickels is 1 less than twice the number of... (answered by fractalier)
A box contains nickels, dimes and quarters worth a total of $2.10. There are twice as... (answered by TimothyLamb)
A box contains nickels, dimes and pennies worth $8.40. The number of dimes is six less... (answered by Fombitz)
A box contains nickels, dimes and pennies worth $6.20. The number of nickels is two less... (answered by lwsshak3)
A box contains nickels, dimes and pennies worth $8.40. The number of dimes is six less... (answered by josgarithmetic,MathTherapy,ikleyn)
Some number of dimes plus Nickels equal $7.20 . the number of dimes is three less than... (answered by macston)
Max has 14 coins consisting of nickels, dimes, and quarters. The total value of the coins (answered by josgarithmetic)