SOLUTION: The length of a rectangle is 8 in. more than twice it's width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.

Question 43003: The length of a rectangle is 8 in. more than twice it's width. If the perimeter of the rectangle is 64 in., find the width of the rectangle.
Found 2 solutions by pwac, jmg:
Answer by pwac(253) (Show Source): You can put this solution on YOUR website!
Let w = width
So length(l) is 2w+8
Perimeter of a rectangle is 2l + 2w
In this case:
2(2w+8)+ 2w = 64. multiply out bracket on left
4w+16+2w = 64
6w+16 = 64 subtract 16 from both sides
6w = 48 divide both sides by 6
w = 8
Width of rectangle is 8 inches
Pete
Answer by jmg(22) (Show Source): You can put this solution on YOUR website!
Set up an equation,
length is 8 more than twice the width : expression would be 2*w + 8
since you let a w stand for width, then width= w
It gives you the Perimeter = 64
Perimeter = 2*length + 2 * width
Fill in the expressions from above
64 = 2(2w + 8) + 2w
64 = 4w + 16 + 2w
64 = 6w + 16
48 = 6w
8 = w
The question asked for the width (w) which is 8
If it had asked for the length you would fill it back into the 2w + 8 and it would be 24.
Hope it helps
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