SOLUTION: The sum of two numbers is 64. Twice the smaller number is 10 less than the larger number. Find the numbers.
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Question 429834: The sum of two numbers is 64. Twice the smaller number is 10 less than the larger number. Find the numbers.
Answer by algebrahouse.com(1659) (Show Source): You can put this solution on YOUR website!
"The sum of two numbers is 64. Twice the smaller number is 10 less than the larger number. Find the numbers."
x = one number
64 - x = other number {sum of two numbers is 64}
2x = 64 - x - 10 {twice smaller is ten less than larger}
2x = 54 - x {combined like terms}
3x = 54 {added x to both sides}
x = 18 {divided both sides by 3}
64 - x = 46 {substituted 18, in for x, into 64 - x}
the two numbers are 18 and 46
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