SOLUTION: The perimeter of a rectangle is 68 inches. The length exceeds the width by 28 inches. Find the length and the width.

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Question 429149: The perimeter of a rectangle is 68 inches. The length exceeds the width by 28 inches. Find the length and the width.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
length exceeds the width by 28 inches.
Let x and (x+28in)represent the width and length respectively
2(x+28) + 2x = 68in
4x = 12in
x = 3in, the width. the length is 31in (3in + 28in)
CHECKING our Answer***
2*31in + 2*3in = 62in + 6in = 68in


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