# SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. let the width of the rectangle is

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 Click here to see ALL problems on Miscellaneous Word Problems Question 42524: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. let the width of the rectangle is x cm then length of the rectangle will be 2x+2 given perimeter of the rectangle is 52 cm =>2*(x+(2x+2))=52 =>2*(3x+2)=52 =>3x+2=26 =>3x=24 =>x=8 hence lenghth of the rectangle is 18cm and width is 8cmFound 2 solutions by Nate, pallavi:Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!width = w length = 2w + 2 width = 8 length = 2w + 2 = 2(8) + 2 = 18 Answer by pallavi(12)   (Show Source):