SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
let the width of the rectangle is
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Question 42524: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
let the width of the rectangle is x cm
then length of the rectangle will be 2x+2
given perimeter of the rectangle is 52 cm
=>2*(x+(2x+2))=52
=>2*(3x+2)=52
=>3x+2=26
=>3x=24
=>x=8
hence lenghth of the rectangle is 18cm and width is 8cm
Found 2 solutions by Nate, pallavi:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
width = w
length = 2w + 2
width = 8
length = 2w + 2 = 2(8) + 2 = 18
Answer by pallavi(12) (Show Source): You can put this solution on YOUR website!
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