SOLUTION: Can you help with this?
a ball is thrown, its height in feet h after t seconds is given:
h=vt-16t^2
v=initial upward velocity in feet per second. if v=21 feet per second, fin
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Question 424391: Can you help with this?
a ball is thrown, its height in feet h after t seconds is given:
h=vt-16t^2
v=initial upward velocity in feet per second. if v=21 feet per second, find all values of t which h=6 feet. Do not round intermediate steps, round answer 2 decimals. THANK YOU!!!!!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a ball is thrown, its height in feet h after t seconds is given:
h = vt - 16t^2
v=initial upward velocity in feet per second.
:
if v=21 feet per second, find all values of t which h=6 feet.
Do not round intermediate steps, round answer 2 decimals.
:
21t - 16t^2 = 6
A quadratic equation
-16t^2 + 21t - 6 = 0
Use the quadratic formula to find t
In this equation; x=t; a=-16; b=21 c=-6
:
:
Two solutions
t =
t = .42 sec, 6 ft on the way up
and
t =
t = .89 sec, 6ft on the way down
:
:
Looks like this:
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