SOLUTION: At present Mary's age is seven times that of her daughter Amy. In ten year's time Mary's age will be three times that of Amy. What are their present ages?
Is it:
7x+10 = 3(x+
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Question 41382: At present Mary's age is seven times that of her daughter Amy. In ten year's time Mary's age will be three times that of Amy. What are their present ages?
Is it:
7x+10 = 3(x+10)
4x = 20
x = 5
therefore: Mary's age = 35 years old
Amy's age = 5 years old
Just wondering..thanks
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
GOOD TO SEE YOUR SINCERE EFFORTS TO SOLVE THE PROBLEM YOUR SELF.KEEP IT UP!
SEE MY COMMENTS BELOW.
At present Mary's age is seven times that of her daughter Amy...SAY X YEARS
SO MARYS AGE IS 7X
IN 10 YEARS THEY WILL BE X+10 AND 7X+10
. In ten year's time Mary's age will be three times that of Amy. What are their present ages?
Is it:
7x+10 = 3(x+10)...............EXCELLENT!!
4x = 20
x = 5...................................PERFECT
therefore: Mary's age = 35 years old
Amy's age = 5 years old
Just wondering..WHY WONDER? BE PROUD AND BE CONFIDENT.SHED YOUR INHIBITIONS.
YOU ARE VERY GOOD AND JUST PROCEED WITH THAT ASSURANCE.WE ARE ALWAYS THERE TO HELP YOU.
thanks
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