SOLUTION: a cars radiator contains 12 L of antifreeze at 25% concentration. how many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50%
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Question 410642: a cars radiator contains 12 L of antifreeze at 25% concentration. how many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50% Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! a cars radiator contains 12 L of antifreeze at 25% concentration.
how many liters must be drained and then replaced by pure antifreeze to bring the concentration to 50%
:
Let x = amt of 25% solution drained, and amt of pure antifreeze to be added
:
.25(12 - x) + x = .50(12)
3 - .25x + x = 6
-.25x + x = 6 - 3
.75x = 3
x =
x = 4 liters drained, and 4 liters of pure antifreeze added
:
:
Check this solution in the original mixture equation
.25(12-4) + 4 = 6
.25(8) + 4 = 6, confirms our solution of 4 liters
