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Question 40961This question is from textbook Algebra structure and method
: This question is from textbook Algebra structure and method

Found 2 solutions by fractalier, psbhowmick:
Answer by fractalier(2101) About Me  (Show Source):
You can put this solution on YOUR website!
Let the rate in the city be r. Thus the rate in the open highway is 2r.
The equation we always use is
Rate * Time = Distance or
RT = D
so we have
r(1) + 2r(4) = 387
9r = 387
r = 43 km/hr

Answer by psbhowmick(489) About Me  (Show Source):
You can put this solution on YOUR website!
Let speed in city = v km/hr.
So speed in highway = 2v km/hr.
Distance traveled in the city in 1 hour at speed 'v' km/hr is 'v' km.
Distance traveled in the highway in 4 hours at speed '2v' km/hr is '8v' km.
So total distance traveled = v + 8v = 9v km
But given total idstance traveled is 387 km.
So 9v = 387
or v = 387/9 = 43
So the speed of bus in the city was 43 km/hr.