SOLUTION: Let the first biker left the ranger station at 'x' hrs.
Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs.
Distance traveled by him = {{{10*(16 - x)}}} miles.
The second bike
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-> SOLUTION: Let the first biker left the ranger station at 'x' hrs.
Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs.
Distance traveled by him = {{{10*(16 - x)}}} miles.
The second bike
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Question 40843: Let the first biker left the ranger station at 'x' hrs.
Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs.
Distance traveled by him = miles.
The second biker left the ranger station 1 hr after the first biker.
So he traveled for ((16 - x) - 1) = (15 - x) hrs.
Distance traveled by him = miles.
As both bikers met at 4 pm so by then they have travelled equal distances.
So
Solving we get x = 13.
Thus the first biker left the ranger station at 13 hrs or 1 pm. Answer by psbhowmick(529) (Show Source):
