# SOLUTION: Let the first biker left the ranger station at 'x' hrs. Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs. Distance traveled by him = {{{10*(16 - x)}}} miles. The second bike

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: Let the first biker left the ranger station at 'x' hrs. Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs. Distance traveled by him = {{{10*(16 - x)}}} miles. The second bike      Log On

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 Question 40843: Let the first biker left the ranger station at 'x' hrs. Then by 4 pm he rode for ((4+12) - x) = (16 - x) hrs. Distance traveled by him = miles. The second biker left the ranger station 1 hr after the first biker. So he traveled for ((16 - x) - 1) = (15 - x) hrs. Distance traveled by him = miles. As both bikers met at 4 pm so by then they have travelled equal distances. So Solving we get x = 13. Thus the first biker left the ranger station at 13 hrs or 1 pm.Answer by psbhowmick(529)   (Show Source):