Hi

A pasture is bounded by a river on one side. 

The farmer has 600 yards for enclosing a rectangular area of 40,000 square yards.

Let x represent the length opposite the river

  x*w = 40,000

    w = 40,000/x

 2(40,000/x) + x = 600

   80,000 + x^2 = 600x

 x^2 -600x + 80,000 = 0

 (x - 200)(x- 400)= 0

I.  (x- 100)= 0  x = 100, the length and 250 are the widths (fence = 600)

II. (x- 400)= 0  x = 400, the length and 100 are the widths (fence = 600) 

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