SOLUTION: A worm is at the bottom of a 12 ft. wall. Every day it crawls up 3 ft., but at night it slips down 2 ft. How many days does it take the worm to get to the top of the wall? How do

Question 40587: A worm is at the bottom of a 12 ft. wall. Every day it crawls up 3 ft., but at night it slips down 2 ft. How many days does it take the worm to get to the top of the wall? How do I solve this?
Found 3 solutions by rajagopalan, JoelSchwartz, MathTherapy:
Answer by rajagopalan(174)   (Show Source): You can put this solution on YOUR website!
Height for climbing 12
Daily climbing rate = 3
daily sipping rate = 2
Net height climbed per day = 1
Like this, on day 9 it will on the 9 foot marking
on day 10 it will reach the top ( 9 + 3) = 12
At the top it need not slip !!
Bravo..
Answer by JoelSchwartz(130)   (Show Source): You can put this solution on YOUR website!

Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

A worm is at the bottom of a 12 ft. wall. Every day it crawls up 3 ft., but at night it slips down 2 ft. How many days does it take the worm to get to the top of the wall? How do I solve this?

days
You can do a check!!
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