SOLUTION: A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account becaus

Question 402038: A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 3718 dollars. How much did he invest at each rate?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
0.06*2x + 0.10x = 3,718
==> 0.12x + 0.10x = 3,718
==> 0.22x = 3,718
==> x = 16,900 $, the investment in the 10%, and
2x = 33,800 $, the investment in the 6%.
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