SOLUTION: Working together, two pipes, A and B, can fill a tank in 4h. It takes pipe A 6h longer than pipe B to fill the tank alone. How long would it take each pipe alone to fill the tank?

Question 39427This question is from textbook Technical mathematics
: Working together, two pipes, A and B, can fill a tank in 4h. It takes pipe A 6h longer than pipe B to fill the tank alone. How long would it take each pipe alone to fill the tank? This question is from textbook Technical mathematics

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Working together, two pipes, A and B, can fill a tank in 4h. It takes pipe A 6h longer than pipe B to fill the tank alone. How long would it take each pipe alone to fill the tank?
Pipe B Data:
Time to fill=x hrs; Rate=(1/x) job/hr
Pipe A Data:
Time to fill=x+6 hrs; Rate=(1/(x+6)) job/hr
Together Data:
Time to fill=4 hrs; Rate=(1/4) job/hr
EQUATION:
1/x + 1/(x+6) = 1/4
Multiply thru by 4x(x+6) to get:
4(x+6)+4x=x(x+6)
4x+24+4x=x^2+6x
x^2-2x-24=0
(x-6)(x+4)=0
x=6 hrs. (time to fill for pipe B)
x+6=12 hrs (time to fill for pipe A)
Cheers,
Stan H.

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