SOLUTION: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square c

Question 39302: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimenters longer and 2 centimeters wider than the first. The area of the second rectangle is 270 square centimeters greater than the first. What are the dimensions of the original rectangle?
Found 2 solutions by Nate, Paul:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
Original:
length = 4w
width = w
Second rectangle:
length: 5 + 4w
width = 2 + w
Equations:
First triangle:

Second triangle:

Answer by Paul(988) (Show Source): You can put this solution on YOUR website!
First rectangle is 4x, and its width is x
Second rectangle is 4x+5 in length and x+2 in width
Area of first is 4x*x=
Area of second =
EQUATION:

13x=260
x=20
4(20)=80
Hence, the dimensions of the original rectangle are 80cm * 20cm.
Paul.
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