SOLUTION: Hello Wonderful Person, I am having a problem with a word algebra problem, that their are similar ones posted, but my answers just do not seem to be correct, so I would appreciat

Question 391577: Hello Wonderful Person,
I am having a problem with a word algebra problem, that their are similar ones posted, but my answers just do not seem to be correct, so I would appreciate any feedback you are willing to give me. The problem is The number n, in millions, of hearing impaired individuals of age x, can be approximated by n=0.00006x^3+0.006x^2-0.1x+1.5. To the nearest million the number of hearing impaired individuals of ages 40 and 55 are,
Here is how I did it,
n=0.00006x^3+0.006x^2-0.1x+1.5
n=0.00006x(55)^3+0.006x(55)^2-0.1x(55)+1.5
answer 18.8 million
For the 45 age people I got 19.5 million persons
My answers just seem wrong somehow, but I think plugging in the numbers is correct!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The problem is The number n, in millions, of hearing impaired individuals of age x, can be approximated by n=0.00006x^3+0.006x^2-0.1x+1.5. To the nearest million the number of hearing impaired individuals of ages 40 and 55 are,
Here is how I did it,
n=0.00006x^3+0.006x^2-0.1x+1.5
n=0.00006x(55)^3+0.006x(55)^2-0.1x(55)+1.5
answer 18.8 million
For the 45 age people I got 19.5 million persons
:
Check your math, I put this equation into my calc and got
x=40; 10.4
x=45; 14.6
x=55; 24.1
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