SOLUTION: 5. Find two consecutive numbers such that 4/7 of the larger exceeds 1/2of the smaller by 5.

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Question 389567: 5. Find two consecutive numbers such that 4/7 of the larger exceeds 1/2of the smaller by 5.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!

Hi
Let x and (x+1) represent the smaller and larger consecutive numbers respectively
Question States***
4/7(x+1) = (1/2)x + 5
solving for x
8(x+1) = 7x + 70 Multiplying both sides of equation by 14
8 + 8x = 7x + 70
x = 62, the smaller number. Larger number is 63
CHECKING our Answer***
4/7*63 = 36 = 1/2*62 + 5 = 36
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