Question 388741:
Walter and his parents are a little unusual. If he does an acceptable job of
doing his chores ,he gets paid $3.33 fo that day. If he does an outstanding
job, he gets paid $3 more. During one 10 day period, Walter received $42.30 for
his work. How many days did he do an acceptable job? How many days did he do
an exceptional job?
Answer by Edwin McCravy(20086)   (Show Source):
You can put this solution on YOUR website!
Let the number of days he does an acceptable job = x.
then the number of days he does an outstanding job = 10-x
He got $3.33 for each of the x days, which amounted to $3.33x
He got $3 more for each of the 10-x days, or $3.33+$3 or $6.33,
which amounted to $6.33(10-x)
Get the equation from this:
(The money he got for all x days when he did an acceptable job)
PLUS
(The money he got for all 10-x days when he did an outstanding job)
EQUALS
$42.30
So the equation is
$3.33x + $6.33(10 - x) = $42.30
3.33x + 6.33(10 - x) = 42.30
Drop the zero
on 42.30, making
it 42.3
3.33x + 6.33(10 - x) = 42.3
Distribute
3.33x + 63.3 - 6.33x = 42.3
combine x terms
-3.00x + 63.3 = 42.3
Drop the zeros
on -3.00x, making
it -3x
-3x + 63.3 = 42.3
subtract 63.3
from both sides:
-63.3 = -63.3
----------------------
-3x = -21
Divide both sides by -3
-3x -21
----- = ----
-3 -3
Cancel the -3's on the
left and divide on the
right
x = 7
The number of days he did an acceptable job = x = 7 days
The number of days he did an outstanding job = 10-x = 10-7 = 3 days
Edwin
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