SOLUTION: To reproduce an old photograph, a photographer charges x dollars to make a negative, 3x/5 dollars for each of the first 10 prints, and x/5 dollars for each print in excess of 10 pr

Question 387715: To reproduce an old photograph, a photographer charges x dollars to make a negative, 3x/5 dollars for each of the first 10 prints, and x/5 dollars for each print in excess of 10 prints. If $45 is the total charge to make a negative and 20 prints from an old photograph, what is the value of x?
Value of x means to solve for x, right? this is how I initially set up the equation:
45=x + 3x/5 + x/5(10) which became 45=x + 3x/5 + 10x/5
this is a GRE question and i'm totally lost. Thanks for your help.
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
equation is x+(3x/5)(10)+(x/5)(10)=45

x+(3x/5)(10)+(x/5)(10)=45
x+6x+2x=45
9x=45
x=5

Answer: x=5
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