SOLUTION: Dan and Gary are fishing. They each have several fishing poles and each pole has several worms on its line. Between the two of them, Dan and Gary have 13 poles. Dan's poles each ha

Question 387713: Dan and Gary are fishing. They each have several fishing poles and each pole has several worms on its line. Between the two of them, Dan and Gary have 13 poles. Dan's poles each have 6 worms on their lines. Gary's poles each have 11 worms on their lines. Dan and Gary have a total of 103 worms on their lines. How many poles does each boy have?
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Let D= number of poles of Dan
Let G= number of poles of Gary

You must solve the following system of equations:
D+G=13
6D+11G= 103

Elimination method, multiply the first equation by -6, so the D terms will subtract out.
-6D-6G = -78
6D+11G = 103

Add the two equations together:
5G = 25
G= 5 Poles by Gary

D+G=13
D+5=13
D= 8 Poles by Dan

Check: See if there are a total of 103 worms
6D + 11G = 103
6*8 + 11*5 = 103
48 + 55 = 103

It checks!!

Dr. Robert J. Rapalje
Seminole State College of Florida

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