How many 3 digit counting numbers are even? This is the arithmetic sequence 100, 102, 104, ··· , 998 an = a1 + (n-1)d To find d: d = 102 - 100 = 104 - 102 = 2 a1 = 100 an = 998 an = a1 + (n-1)d 998 = 100 + (n-1)(2) 998 = 100 + 2(n-1) 998 = 100 + 2n - 2 998 = 98 + 2n 900 = 2n 450 = n So there are 450 three-digit counting numbers Edwin AnlytcPhil@aol.com