# SOLUTION: Girard wishes to mix red grapes worth \$1.90 a pound with green grapes worth \$1.10 a pound to get a 24 pound mixture worth \$1.50 a pound. How many pounds of each does he need? pl

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: Girard wishes to mix red grapes worth \$1.90 a pound with green grapes worth \$1.10 a pound to get a 24 pound mixture worth \$1.50 a pound. How many pounds of each does he need? pl      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Word Problems: Miscellaneous Word Problems Solvers Lessons Answers archive Quiz In Depth

 Question 385313: Girard wishes to mix red grapes worth \$1.90 a pound with green grapes worth \$1.10 a pound to get a 24 pound mixture worth \$1.50 a pound. How many pounds of each does he need? please help meAnswer by mananth(12270)   (Show Source): You can put this solution on YOUR website!Girard wishes to mix red grapes worth \$1.90 a pound with green grapes worth \$1.10 a pound to get a 24 pound mixture worth \$1.50 a pound. How many pounds of each does he need? ... red grapes worth \$1.90 a pound ................x pounds green grapes worth \$1.10 a pound ..............24-x mixture 24 pound mixture worth \$1.50 a pound. .. 1.90x+1.10(24-x)=24*1.50 1.90x+26.4-1.10x=36 0.8x+26.4=36 -26.4 -26.4 0.8x=9.6 /0.8 x=12 pounds of red grapes 12 pounds of green grapes ... m.ananth@hotmail.ca