SOLUTION: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution to get a 30% solution?

Question 384535: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution to get a 30% solution?
Answer by mtmorro(23) (Show Source): You can put this solution on YOUR website!
10% alcohol to be mixed with a 50 liters of 80% solution to get a 30% solution
Looks like 125 liters of 10% to make an 80% solution a 30% solution
start with 50 liter of 80%
when 150 liters of 10% this is how it works lets go in deluting step by step.
50 liter of 10% added to 50 liter of 80% divide in have 40% then add you 10% so with 100 liter you are at 50% with 50 liters added so it is now 100 liters
so now do the same thing add 100 liters to the current 100 then it divides by half to 20% now add the 10% you get 30% from the starting 50 liters of 80% solution.
What needs to be 50 liter than another 100 liter of 10% for a total of 150 liters added

so adding 150 liters of 10% to 50 liter of 80% = 30% but at this time there will be 200 liters anwser 150 liters of 10% solution

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