SOLUTION: The sum of two numbers is 47. One number is 5 more than twice the other number. Find the number.
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Question 378601: The sum of two numbers is 47. One number is 5 more than twice the other number. Find the number.
Found 2 solutions by Wingsong, Alan3354:
Answer by Wingsong(2) (Show Source): You can put this solution on YOUR website!
14
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x + y = 47
x = 2y + 5
sub for x in eqn 1
(2y+5) + y = 47
3y+5 = 47
3y = 42
y = 14
the other number = 33
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