SOLUTION: The area of a garden is 1920 square feet, and the length of its diagonal is 68 feet. Find the dimensions of the garden.

Question 361900: The area of a garden is 1920 square feet, and the length of its diagonal is 68 feet. Find the dimensions of the garden.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
The area of a garden is 1920 square feet, and the length of its diagonal is 68 feet. Find the dimensions of the garden.
..
area = L*W=1920
diagonal = 68
..
L=1920/W
..
use pythagoras theorem
(1920/w)^2+w^2=68^2
3686400 +w^4=4625w^2
w^4-4625^2+3686400=0
use quadratic formula
discriminant = 6605025
x1=(4625+sqrt(6645025))/2
x1=w^2 (taking only positve values of w^2)& rounding off The decimals
x1= 3601.39
Take square root we w=60
length = 1920/60
Length = 30
The dimensions are 60 by 32
...
m.ananth@hotmail.ca
60*32= 1920
RELATED QUESTIONS
The area of a garden is 972 square feet, and the length of its diagonal is 45 feet. Find... (answered by mananth,ikleyn)

the length of a rectangular garden is 6 feet longer than its width if the area of the... (answered by macston)

A small vegetable garden has an area of 80 square feet. Its length is 2 feet more than... (answered by checkley79)

The Length of Hillcrest Garden is 6 feet more than its width. A walkway 3 feet wide... (answered by checkley77)

The length of a rectangular garden is 6 feet longer than its width. If the area of the... (answered by Alan3354)

The length of a rectangular flower garden is four feet more than its width. The area is... (answered by ReadingBoosters)

The perimeter of a garden is 20 feet. The area of the garden is 26 square feet. Draw this (answered by josgarithmetic,ikleyn)

The length of a rectangular garden is 5 feet longer than its width. The garden is... (answered by mathanator)

A garden has an area of 320 square feet. It's length is 4 feet more than its width. What... (answered by addingup)