SOLUTION: A 490m piece of rope is cut into three pieces. The first piece is three times the second. The third is 23 less than the first. How long are the pieces?
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Question 357341: A 490m piece of rope is cut into three pieces. The first piece is three times the second. The third is 23 less than the first. How long are the pieces?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
F=3S
T=F-23
*******
F+S+T=490
(3S)+S+(3S-23)=490
7S=490+23
7S=513
S=513/7
S=73.286 IS THE SECOND PIECE.
F=3*73.286=219.857 IS THE FIRST PIECE.
T=219.857-234=196.857 IS THE THIRD PIECE.
PROOF:
219.857+73.286+196.857=490
490=490
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