SOLUTION: The length of a rectangle is twice the width. if the length is increased by 4 inches and the width is decreased by 1 inch, a new rectangle is formed whose perimeter is 198 inches.

Question 357329: The length of a rectangle is twice the width. if the length is increased by 4 inches and the width is decreased by 1 inch, a new rectangle is formed whose perimeter is 198 inches. find the dimesions of the originional rectangle
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi,

Let w represent te original width.  Than 2w will be the original length

2*l + 2*w = P (all the way around the rectangle)

2*(2w+ 4")+ 2( w- 1") = 198"

simplify ans Solve

4w + 8 + 2w -2 = 198"

6w = 192"

w = 32"

Original triangle was 32" wide and 64" long

check your answer

2*68 + 2* 31 = 198 

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