SOLUTION: In testing a hybrid engine, engineers are trying various mixtures of gasoline and methanol. How much of a 90% gasoline mixture and a 75% gasoline mixture would be needed for 600 L

Question 356576: In testing a hybrid engine, engineers are trying various mixtures of gasoline and methanol. How much of a 90% gasoline mixture and a 75% gasoline mixture would be needed for 600 L of an 85% gasoline mixture?

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let A be the amount of 90% mixture, B the amount of 75% mixture.
Volume:
1.
Concentration:

2.
Multiply eq. 1 by (-15) and add to eq. 2 to eliminate B and solve for A.

ml
Then from eq. 1,

ml
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