SOLUTION: A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 6 liters of a 50% iodine mixture?

Question 353723: A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 6 liters of a 50% iodine mixture?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A pharmacist has 40% and 80% of iodine solutions on hand. How many liters of each iodine solution will be required to produce 6 liters of a 50% iodine mixture?
.
Let x = liters of 40% iodine
then
6-x = liters of 80% iodine
.
.40x + .80(6-x) = .50(6)
.40x + 4.80-.80x = 3
4.80-.40x = 3
-.40x = -1.80
x = 4.5 liters (40% iodine)
.
80% iodine:
6-x = 6-4.5 = 1.5 (80% iodine)
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