SOLUTION: I don't even know where to begin on this problem. This is a question from my college Algebra 2 course. A precious metals company receives an order for a block of 160 lbs. of al

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Misc -> SOLUTION: I don't even know where to begin on this problem. This is a question from my college Algebra 2 course. A precious metals company receives an order for a block of 160 lbs. of al      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Miscellaneous Word Problems Solvers Lessons Answers archive Quiz In Depth

 Question 353420: I don't even know where to begin on this problem. This is a question from my college Algebra 2 course. A precious metals company receives an order for a block of 160 lbs. of alloy which is 35% silver. The block is made from two individual blocks. The first individual block was 50% silver. The second individual block was 25% silver. What were the weights of the two original blocks?Answer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!Think about the amount of silver in each of the blocks of alloy. The 160-lb block has 35% of 160 lbs of silver, or (0.35)(160) lbs of silver. The two blocks from which this is made have x(0.5) lbs of silver and (160-x)(0.25) lbs of silver. x is the weight of the block with 50% silver. So we set these quantities equal. (0.35)(160) = x(0.50)+(160-x)(0.25) Simplify and solve for x. 56 = 0.5x+40-0.25x Subtract 40 from both sides. 16 = 0.5x-0.25x Simplify. 16 = 0.25x Divide both sides by 0.25 64 = x and... 160-x = 96 The weights of the original blocks were: 64 lbs of the 50% silver alloy and 96 lbs of the 25% silver alloy.