SOLUTION: A rock is tossed into the air at t = 0 seconds from a building 30 feet above the ground. Its height, in feet above the ground, as a function of time is given by .

Question 353196: A rock is tossed into the air at t = 0 seconds from a building 30 feet above the ground. Its height, in feet above the ground, as a function of time is given by .
Found 2 solutions by solver91311, Fombitz:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Let represent the magnitude of the vertical component of initial velocity vector imparted to the rock by the entity tossing the rock measured in feet per second. If the entity throwing the rock was so configured that the rock was at some distance in feet above the 30 foot high roof, then the height as a function of time at seconds would be given by:

John

My calculator said it, I believe it, that settles it

Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
By thrown into the air, I'm assuming you gave it a velocity in the opposite direction of gravity.
I'll call that velocity, .
At time, , the rock is at 30 feet elevation.
The ground is at 0 feet.
.
.
.

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