SOLUTION: Two joggers, one averaging 6 mph and one averaging 5 mph, start from a designated initial point. The slower jogger arrives at the end of the run 15 minutes after the other jogger.

Question 351579: Two joggers, one averaging 6 mph and one averaging 5 mph, start from a designated initial point. The slower jogger arrives at the end of the run 15 minutes after the other jogger. Find the distance of the run.
Answer by sofiyac(983) (Show Source): You can put this solution on YOUR website!
distance=time*speed
Since they are each running the same distance, speed*time of first jogger will equal speed*time of the second jogger.
Let the time of the fast jogger be t then the time of the slower jogger is t+15

subtract 5t from each side
so the time of faster jogger is 75 minutes which is 1.25 hours.
Then we use the distance formula to find the distance
distance=6*1.25=7.5 miles
RELATED QUESTIONS
Two Joggers, one averaging 9 mph and one averaging 5 mph, start from a designated initial (answered by ankor@dixie-net.com)

Two joggers, one averaging 7 mph and one averaging 4 mph, start from a designated initial (answered by richwmiller)

2 joggers, 1 averaging 9 mph and 1 averaging 6 mph, start from a designated initial... (answered by josgarithmetic)

Two joggers, one averaging 5 mph and one averaging 4 mph, start... (answered by josgarithmetic,ikleyn)

Two joggers, one averaging 7mph and one averaging 4mph, start from a disgnated initial... (answered by josgarithmetic)

This is from a worksheet given by my professor, not from a textbook. Two bicyclists,... (answered by ankor@dixie-net.com)

Two cars start together and head east, one averaging 42 mph and the other averaging 53... (answered by josmiceli)

Point A and point B are 270 miles apart. One jogger is at point A, and another jogger... (answered by josmiceli)

Two runners one averaging 5 miles per hour and the other one averaging 4 miles per hour,... (answered by josgarithmetic)