SOLUTION: A train, after traveling for 3 hours, was detained 40 minutes. Then it proceeded at 5/6 its former rate and arrived 10 minutes late. If the delay had occurred at a point 15 kilomet
Algebra.Com
Question 347474: A train, after traveling for 3 hours, was detained 40 minutes. Then it proceeded at 5/6 its former rate and arrived 10 minutes late. If the delay had occurred at a point 15 kilometers farther from its destination, the train would have been only 5 minutes late. Find the rate of the train and the total distance traveled.
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
The train cannot arrive 5 minutes earlier if the delay happens sooner ("farther
from its destination"), because the post-delay speed is slower. There is a
typo here.
RELATED QUESTIONS
A train, after travelling for 3 hours, was detained 40 minutes. Then it proceeded at 6/5... (answered by ankor@dixie-net.com)
A train, an hour after starting, meets with an accident which detains it an hour, after... (answered by ankor@dixie-net.com)
A train after traveling 150 km meets with an accident and then proceeds with 3/5 of its... (answered by ankor@dixie-net.com)
A train, an hour after starting, meets an accident which detains it one hour, after which (answered by Fermat)
A bus started from town A for town B, 160 km away. After traveling 20 km, it was detained (answered by geetha_rama)
a train, an hour after starting, meets with an accident which detains it an hour .after... (answered by ankor@dixie-net.com)
Hi
A train after travelling 50km meets an accident and and after reducing 3/4 of its... (answered by mananth,ikleyn)
Below are two questions that I was able to see the answer for in the answer key, but have (answered by solver91311,Edwin McCravy,Earlsdon)
A train arrived at its destination at 3:15 P.M. if the trip took 1 hour and 10 minutes,... (answered by Amateur)