SOLUTION: The length of a rectangular field is 45 ft greater than its width. How much fencing is needed to enclose the field and divide it into two parts?

Question 343704: The length of a rectangular field is 45 ft greater than its width. How much fencing is needed to enclose the field and divide it into two parts?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of a rectangular field is 45 ft greater than its width. How much fencing is needed to enclose the field and divide it into two parts?
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Let the width be "W".
Then Length = W+45
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Draw a picture and label the line segments.
Two Solutions:
3(W+45)+ 2w = 3W+135+2W = 5W+135 ft
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OR
3(W)+2(W+45) = 3W+2W+90 = 5W+90 ft
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The anwer depends on where you put the dividing side.
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Cheers,
Stan H.
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