SOLUTION: The distance d, in feet, a bomb falls in t seconds is given by {{{d = (16t^2)/(1+.06t) }}} How many seconds are required for a bomb released at 21,000 feet to reach its targ

Question 34252: The distance d, in feet, a bomb falls in t seconds is given by
How many seconds are required for a bomb released at 21,000 feet to reach its target? (If necessary, round your answer to two decimal places.)

A) 1167.12 seconds

B) 185.76 seconds

C) 92.88 seconds

D) 2972.19 seconds

Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=183225 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 92.8809868145612, -14.1309868145612. Here's your graph:

(C)
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