SOLUTION: A ball is thrown straight upward at an initial speed of 149 feet per second.
h=-16⁢t2+149⁢t
When does the ball reach the highest point?
Algebra.Com
Question 339928: A ball is thrown straight upward at an initial speed of 149 feet per second.
h=-16t2+149t
When does the ball reach the highest point?
Found 2 solutions by nerdybill, solver91311:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Given:
h = -16t^2 + 149t
.
The time (t) when it reaches the "ighest" point would be at the "axis of symmetry":
t = -b/2a = -149/(2*(-16)) = -149/(-32) = 4.66 sec
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ -16t^2\ +\ 149t)
is only true if the ball was launched from the ground at 149 feet per second initial velocity. Typically when you throw something upward, the ball is above the ground by a distance that is in proportion to the thrower's height.
Be that as it may, the function describes a parabola opening downward. The maximum height is reached at the value of 
for the vertex of the parabola. Use 
where 
and 
By the way, 149 feet per second is roughly 101.5 miles per hour, very close to the top speed of a pitched baseball. Find me the guy who can throw a ball straight up at that velocity.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
a ball is thrown straight upward at an initial speed of 240 feet per second. From... (answered by TimothyLamb)
A ball is thrown straight upward at an initial speed of 136 feet per seconds.
From... (answered by solver91311)
A ball is thrown straight upward at an initial speed of 203 feet per second.
From... (answered by nerdybill,josmiceli)
A ball is thrown straight upward at an initial speed of 104 feet per seconds. From... (answered by scott8148,stanbon)
A ball is thrown upward with an initial velocity of 50 feet per second. The height h (in... (answered by KMST)
A ball is thrown straight upward from the top of a building 50 feet tall at an initial... (answered by fractalier)
Please help me solve this equation:
A ball is thrown upward with an initial velocity... (answered by KnightOwlTutor)
A ball is thrown upward with an initial velocity of 64 feet/ sec. using h(t)= 64 t-16 t... (answered by Cromlix)
In physics, one learns that the height of an object thrown upward from an initial height... (answered by Boreal)