SOLUTION: Find the vertex, line of symestry, and the line of symmestry, and the maximum or minimum value of fx)=-x^2+12x+3

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Question 334236: Find the vertex, line of symestry, and the line of symmestry, and the maximum or minimum value of
fx)=-x^2+12x+3
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Convert to vertex form,y=a%28x-h%29%5E2%2Bk where (h,k) is the vertex.
y=-x%5E2%2B12x%2B3
y=-%28x%5E2-12x%2B36%29%2B3%2B36
y=-%28x-6%29%5E2%2B39
The vertex is (6,39).
The vertex lies on the axis of symmetry, x=6
The parabola opens downwards since the coefficient of the x%5E2 term is negative and the vertex value is a maximum.
ymax=39
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.
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