SOLUTION: What ever shall I do to solve this problem? Two pipes can fill a large tank in 10 hours. One of the pipes, used alone, takes 15 hours longer than the other to fill the tank. How

Question 324678: What ever shall I do to solve this problem?
Two pipes can fill a large tank in 10 hours. One of the pipes, used alone, takes 15 hours longer than the other to fill the tank. How long would each pipe take to fill the tank alone?
Found 2 solutions by stanbon, Fombitz:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two pipes can fill a large tank in 10 hours. One of the pipes, used alone, takes 15 hours longer than the other to fill the tank. How long would each pipe take to fill the tank alone?
----------------
2-pipes DATA:
time = 10 hr/job ; rate = 1/10 job/hr
-------------------------
1-pipe DATA:
time = 15 hr/job ; rate = 1/15 job/hr
-----
Other pipe DATA:
time = x hr/job ; rate = 1/x job/hr
---------------------------------------
Equation:
rate + rate = together rate
1/x + 1/15 = 1/10
---
Multiply thru by 30x to get:
30 + 2x = 3x
x = 30 hr. (time required by "Other" pipe)
========================
Cheers,
Stan H.
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Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Rate*Time=Output
Let Pipe 1's rate be R1, Let Pipe 2's rate be R2.
The output will be 1 to fill the large tank.
1.
2.
3.
From eq. 1,

From eq. 2,

From eq. 3,

Equate the t equations,

4.
From above,

Substitute into eq. 4,

You can factor this quadratic,

Only a positive rate makes sense in this case.

Then from eq. 1,

.
.
.

hrs
.
.
.

hrs
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