SOLUTION: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320 lb mixture that is 10% protein?
How many pounds of the
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Question 317426: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320 lb mixture that is 10% protein?
How many pounds of the cornmeal should be in the mixture?
How many pounds of the soybean meal should be in mixture?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
soybean is 16% protein.
cornmeal is 8% protein.
x = amount of soybeans
y = amount of cornmeal
x + y = 320
amount of protein in 320 pound mixture if equal to .10 * 320 = 32
amount of protein in x pounds of soybeans is .16 * x
amount of protein in 6 pounds of cornmeal is .08 * y
.16*x + .08*y = .10*320
You have 2 equations that need to be solved simultaneously.
They are:
x + y = 320
.16x + .08y = 32
sole for y in the first equation to get:
y = 320 - x
substitute in the second equation to get:
.16x + .08(320-x) = 32 pounds of protein in the mixture.
simplify to get:
.16x + 25.6 - .08x = 32
combine like terms to get:
.08x + 25.6 = 32
subtract 25.6 from both sides of the equation to get:
.08x = 6.4
divide both sides of the equation by .08 to get:
x = 80
You need 80 pounds of soybeans which means you need 240 pounds of cornmeal.
.16*80 + .08*240 = 12.8 + 19.2 = 32 pounds of protein.
answer is you need 80 pounds of soybeans and 240 pounds of cornmeal.
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