# SOLUTION: Fast food. If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? For this problem I subtracted one from every five and

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 Click here to see ALL problems on Miscellaneous Word Problems Question 307281: Fast food. If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? For this problem I subtracted one from every five and received the answer 111. Found 2 solutions by Alan3354, checkley77:Answer by Alan3354(31518)   (Show Source): You can put this solution on YOUR website!Fast food. If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? For this problem I subtracted one from every five and received the answer 111. --------------------------- I don't see how you got 111. 4 out of 5 is 4/5 = 0.8 0.8*445 = 356 Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!4 out of 5 is: 4/5=.8 or 80% prefer fast food. .8*445=356 ans. for the number of doctors who prefer fast food.